4(3x+1)=40+3

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Solution for 4(3x+1)=40+3 equation: 



4(3x+1)=40+3

We move all terms to the left:

4(3x+1)-(40+3)=0

We add all the numbers together, and all the variables

4(3x+1)-43=0

We multiply parentheses

12x+4-43=0

We add all the numbers together, and all the variables

12x-39=0

We move all terms containing x to the left, all other terms to the right

12x=39

x=39/12

x=3+1/4

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