3(y+4)=-3(2y-1)+3y

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Solution for 3(y+4)=-3(2y-1)+3y equation: 



3(y+4)=-3(2y-1)+3y

We move all terms to the left:

3(y+4)-(-3(2y-1)+3y)=0

We multiply parentheses

3y-(-3(2y-1)+3y)+12=0



We calculate terms in parentheses: -(-3(2y-1)+3y), so:

-3(2y-1)+3y

We add all the numbers together, and all the variables

3y-3(2y-1)

We multiply parentheses

3y-6y+3

We add all the numbers together, and all the variables

-3y+3

Back to the equation:

-(-3y+3)



We get rid of parentheses

3y+3y-3+12=0

We add all the numbers together, and all the variables

6y+9=0

We move all terms containing y to the left, all other terms to the right

6y=-9

y=-9/6

y=-1+1/2

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