1/4(3x-12)=2x+5-6x

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Solution for 1/4(3x-12)=2x+5-6x equation: 



1/4(3x-12)=2x+5-6x

We move all terms to the left:

1/4(3x-12)-(2x+5-6x)=0



Domain of the equation: 4(3x-12)!=0

x∈R



We add all the numbers together, and all the variables

1/4(3x-12)-(-4x+5)=0

We get rid of parentheses

1/4(3x-12)+4x-5=0

We multiply all the terms by the denominator


4x*4(3x-12)-5*4(3x-12)+1=0

Wy multiply elements

16x^2(3-20x(3+1=0

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