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3x/4x+5/8=4x
We move all terms to the left:
3x/4x+5/8-(4x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-4x+3x/4x+5/8=0
We calculate fractions
-4x+24x/32x+20x/32x=0
We multiply all the terms by the denominator
-4x*32x+24x+20x=0
We add all the numbers together, and all the variables
44x-4x*32x=0
Wy multiply elements
-128x^2+44x=0
a = -128; b = 44; c = 0;
Δ = b2-4ac
Δ = 442-4·(-128)·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-44}{2*-128}=\frac{-88}{-256} =11/32 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+44}{2*-128}=\frac{0}{-256} =0 $
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