3(y+3)=2(y-2)-6

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Solution for 3(y+3)=2(y-2)-6 equation: 



3(y+3)=2(y-2)-6

We move all terms to the left:

3(y+3)-(2(y-2)-6)=0

We multiply parentheses

3y-(2(y-2)-6)+9=0



We calculate terms in parentheses: -(2(y-2)-6), so:

2(y-2)-6

We multiply parentheses

2y-4-6

We add all the numbers together, and all the variables

2y-10

Back to the equation:

-(2y-10)



We get rid of parentheses

3y-2y+10+9=0

We add all the numbers together, and all the variables

y+19=0

We move all terms containing y to the left, all other terms to the right

y=-19

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