13=4(z+12)-3

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Solution for 13=4(z+12)-3 equation: 



13=4(z+12)-3

We move all terms to the left:

13-(4(z+12)-3)=0



We calculate terms in parentheses: -(4(z+12)-3), so:

4(z+12)-3

We multiply parentheses

4z+48-3

We add all the numbers together, and all the variables

4z+45

Back to the equation:

-(4z+45)



We get rid of parentheses

-4z-45+13=0

We add all the numbers together, and all the variables

-4z-32=0

We move all terms containing z to the left, all other terms to the right

-4z=32

z=32/-4

z=-8

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