50=-5t2+30t+25

Solution for 50=-5t2+30t+25 equation:

50=-5t^2+30t+25

We move all terms to the left:

50-(-5t^2+30t+25)=0

We get rid of parentheses

5t^2-30t-25+50=0

We add all the numbers together, and all the variables

5t^2-30t+25=0

a = 5; b = -30; c = +25;
Δ = b2-4ac
Δ = -302-4·5·25
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-20}{2*5}=\frac{10}{10}
=1
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+20}{2*5}=\frac{50}{10}
=5
$