3(y+2)=3y+4+2

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Solution for 3(y+2)=3y+4+2 equation: 



3(y+2)=3y+4+2

We move all terms to the left:

3(y+2)-(3y+4+2)=0

We add all the numbers together, and all the variables

3(y+2)-(3y+6)=0

We multiply parentheses

3y-(3y+6)+6=0

We get rid of parentheses

3y-3y-6+6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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