(n-2)-2(n-3)=3(2n+1)+1

Solution for (n-2)-2(n-3)=3(2n+1)+1 equation:

(n-2)-2(n-3)=3(2n+1)+1

We move all terms to the left:

(n-2)-2(n-3)-(3(2n+1)+1)=0

We multiply parentheses

(n-2)-2n-(3(2n+1)+1)+6=0

We get rid of parentheses

n-2n-(3(2n+1)+1)-2+6=0


We calculate terms in parentheses: -(3(2n+1)+1), so:

3(2n+1)+1

We multiply parentheses

6n+3+1

We add all the numbers together, and all the variables

6n+4

Back to the equation:

-(6n+4)


We add all the numbers together, and all the variables

-1n-(6n+4)+4=0

We get rid of parentheses

-1n-6n-4+4=0

We add all the numbers together, and all the variables

-7n=0

n=0/-7

n=0