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5(x+2)+x-3=2(x+12)+35
We move all terms to the left:
5(x+2)+x-3-(2(x+12)+35)=0
We add all the numbers together, and all the variables
x+5(x+2)-(2(x+12)+35)-3=0
We multiply parentheses
x+5x-(2(x+12)+35)+10-3=0
We calculate terms in parentheses: -(2(x+12)+35), so:We add all the numbers together, and all the variables
2(x+12)+35
We multiply parentheses
2x+24+35
We add all the numbers together, and all the variables
2x+59
Back to the equation:
-(2x+59)
6x-(2x+59)+7=0
We get rid of parentheses
6x-2x-59+7=0
We add all the numbers together, and all the variables
4x-52=0
We move all terms containing x to the left, all other terms to the right
4x=52
x=52/4
x=13
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