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(24+x)(600-12x)=0
We add all the numbers together, and all the variables
(x+24)(-12x+600)=0
We multiply parentheses ..
(-12x^2+600x-288x+14400)=0
We get rid of parentheses
-12x^2+600x-288x+14400=0
We add all the numbers together, and all the variables
-12x^2+312x+14400=0
a = -12; b = 312; c = +14400;
Δ = b2-4ac
Δ = 3122-4·(-12)·14400
Δ = 788544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{788544}=888$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(312)-888}{2*-12}=\frac{-1200}{-24} =+50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(312)+888}{2*-12}=\frac{576}{-24} =-24 $
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