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3(y+2)=-4(2y-1)+5y
We move all terms to the left:
3(y+2)-(-4(2y-1)+5y)=0
We multiply parentheses
3y-(-4(2y-1)+5y)+6=0
We calculate terms in parentheses: -(-4(2y-1)+5y), so:We get rid of parentheses
-4(2y-1)+5y
We add all the numbers together, and all the variables
5y-4(2y-1)
We multiply parentheses
5y-8y+4
We add all the numbers together, and all the variables
-3y+4
Back to the equation:
-(-3y+4)
3y+3y-4+6=0
We add all the numbers together, and all the variables
6y+2=0
We move all terms containing y to the left, all other terms to the right
6y=-2
y=-2/6
y=-1/3
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