-3(-7u+2)-3u=2(u-6)-8

Solution for -3(-7u+2)-3u=2(u-6)-8 equation:

-3(-7u+2)-3u=2(u-6)-8

We move all terms to the left:

-3(-7u+2)-3u-(2(u-6)-8)=0

We add all the numbers together, and all the variables

-3u-3(-7u+2)-(2(u-6)-8)=0

We multiply parentheses

-3u+21u-(2(u-6)-8)-6=0


We calculate terms in parentheses: -(2(u-6)-8), so:

2(u-6)-8

We multiply parentheses

2u-12-8

We add all the numbers together, and all the variables

2u-20

Back to the equation:

-(2u-20)


We add all the numbers together, and all the variables

18u-(2u-20)-6=0

We get rid of parentheses

18u-2u+20-6=0

We add all the numbers together, and all the variables

16u+14=0

We move all terms containing u to the left, all other terms to the right

16u=-14

u=-14/16

u=-7/8