-2/2(6-9x)=-1/5(15x+10)

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Solution for -2/2(6-9x)=-1/5(15x+10) equation:



-2/2(6-9x)=-1/5(15x+10)
We move all terms to the left:
-2/2(6-9x)-(-1/5(15x+10))=0
Domain of the equation: 2(6-9x)!=0
x∈R
Domain of the equation: 5(15x+10))!=0
x∈R
We add all the numbers together, and all the variables
-2/2(-9x+6)-(-1/5(15x+10))=0
We calculate fractions
(-10x1/(2(-9x+6)*5(15x+10)))+(-(-2x0)/(2(-9x+6)*5(15x+10)))=0
We calculate terms in parentheses: +(-10x1/(2(-9x+6)*5(15x+10))), so:
-10x1/(2(-9x+6)*5(15x+10))
We multiply all the terms by the denominator
-10x1
We add all the numbers together, and all the variables
-10x
Back to the equation:
+(-10x)
We calculate terms in parentheses: +(-(-2x0)/(2(-9x+6)*5(15x+10))), so:
-(-2x0)/(2(-9x+6)*5(15x+10))
We add all the numbers together, and all the variables
-(-2x)/(2(-9x+6)*5(15x+10))
We multiply all the terms by the denominator
-(-2x)
We get rid of parentheses
2x
Back to the equation:
+(2x)
We add all the numbers together, and all the variables
2x+(-10x)=0
We get rid of parentheses
2x-10x=0
We add all the numbers together, and all the variables
-8x=0
x=0/-8
x=0

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