3(x-8)+20=2(x-5)

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Solution for 3(x-8)+20=2(x-5) equation:



3(x-8)+20=2(x-5)
We move all terms to the left:
3(x-8)+20-(2(x-5))=0
We multiply parentheses
3x-(2(x-5))-24+20=0
We calculate terms in parentheses: -(2(x-5)), so:
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
We add all the numbers together, and all the variables
3x-(2x-10)-4=0
We get rid of parentheses
3x-2x+10-4=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6

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