29(4-3x)+12=7x-5(2x-7)

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Solution for 29(4-3x)+12=7x-5(2x-7) equation: 



29(4-3x)+12=7x-5(2x-7)

We move all terms to the left:

29(4-3x)+12-(7x-5(2x-7))=0

We add all the numbers together, and all the variables

29(-3x+4)-(7x-5(2x-7))+12=0

We multiply parentheses

-87x-(7x-5(2x-7))+116+12=0



We calculate terms in parentheses: -(7x-5(2x-7)), so:

7x-5(2x-7)

We multiply parentheses

7x-10x+35

We add all the numbers together, and all the variables

-3x+35

Back to the equation:

-(-3x+35)



We add all the numbers together, and all the variables

-87x-(-3x+35)+128=0

We get rid of parentheses

-87x+3x-35+128=0

We add all the numbers together, and all the variables

-84x+93=0

We move all terms containing x to the left, all other terms to the right

-84x=-93

x=-93/-84

x=1+3/28

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