10(x-2)=7-12(x+1)

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Solution for 10(x-2)=7-12(x+1) equation: 



10(x-2)=7-12(x+1)

We move all terms to the left:

10(x-2)-(7-12(x+1))=0

We multiply parentheses

10x-(7-12(x+1))-20=0



We calculate terms in parentheses: -(7-12(x+1)), so:

7-12(x+1)

determiningTheFunctionDomain
-12(x+1)+7

We multiply parentheses

-12x-12+7

We add all the numbers together, and all the variables

-12x-5

Back to the equation:

-(-12x-5)



We get rid of parentheses

10x+12x+5-20=0

We add all the numbers together, and all the variables

22x-15=0

We move all terms containing x to the left, all other terms to the right

22x=15

x=15/22

x=15/22

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