2x-4(x-6)=15+3(x-1)

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Solution for 2x-4(x-6)=15+3(x-1) equation: 



2x-4(x-6)=15+3(x-1)

We move all terms to the left:

2x-4(x-6)-(15+3(x-1))=0

We multiply parentheses

2x-4x-(15+3(x-1))+24=0



We calculate terms in parentheses: -(15+3(x-1)), so:

15+3(x-1)

determiningTheFunctionDomain
3(x-1)+15

We multiply parentheses

3x-3+15

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

-2x-(3x+12)+24=0

We get rid of parentheses

-2x-3x-12+24=0

We add all the numbers together, and all the variables

-5x+12=0

We move all terms containing x to the left, all other terms to the right

-5x=-12

x=-12/-5

x=2+2/5

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