3(x-8)+1=2-4(x+1)

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Solution for 3(x-8)+1=2-4(x+1) equation: 



3(x-8)+1=2-4(x+1)

We move all terms to the left:

3(x-8)+1-(2-4(x+1))=0

We multiply parentheses

3x-(2-4(x+1))-24+1=0



We calculate terms in parentheses: -(2-4(x+1)), so:

2-4(x+1)

determiningTheFunctionDomain
-4(x+1)+2

We multiply parentheses

-4x-4+2

We add all the numbers together, and all the variables

-4x-2

Back to the equation:

-(-4x-2)



We add all the numbers together, and all the variables

3x-(-4x-2)-23=0

We get rid of parentheses

3x+4x+2-23=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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