y-3=2(3y-1)

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Solution for y-3=2(3y-1) equation: 



y-3=2(3y-1)

We move all terms to the left:

y-3-(2(3y-1))=0



We calculate terms in parentheses: -(2(3y-1)), so:

2(3y-1)

We multiply parentheses

6y-2

Back to the equation:

-(6y-2)



We get rid of parentheses

y-6y+2-3=0

We add all the numbers together, and all the variables

-5y-1=0

We move all terms containing y to the left, all other terms to the right

-5y=1

y=1/-5

y=-1/5

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