2(3x-2)=3(x+3)+2

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Solution for 2(3x-2)=3(x+3)+2 equation: 



2(3x-2)=3(x+3)+2

We move all terms to the left:

2(3x-2)-(3(x+3)+2)=0

We multiply parentheses

6x-(3(x+3)+2)-4=0



We calculate terms in parentheses: -(3(x+3)+2), so:

3(x+3)+2

We multiply parentheses

3x+9+2

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)



We get rid of parentheses

6x-3x-11-4=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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