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3(x-5)=2(2x+5)
We move all terms to the left:
3(x-5)-(2(2x+5))=0
We multiply parentheses
3x-(2(2x+5))-15=0
We calculate terms in parentheses: -(2(2x+5)), so:We get rid of parentheses
2(2x+5)
We multiply parentheses
4x+10
Back to the equation:
-(4x+10)
3x-4x-10-15=0
We add all the numbers together, and all the variables
-1x-25=0
We move all terms containing x to the left, all other terms to the right
-x=25
x=25/-1
x=-25
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