2/5x+7/3x=1

Solution for 2/5x+7/3x=1 equation:

2/5x+7/3x=1

We move all terms to the left:

2/5x+7/3x-(1)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We calculate fractions


6x/15x^2+35x/15x^2-1=0

We multiply all the terms by the denominator


6x+35x-1*15x^2=0

We add all the numbers together, and all the variables

41x-1*15x^2=0

Wy multiply elements

-15x^2+41x=0

a = -15; b = 41; c = 0;
Δ = b2-4ac
Δ = 412-4·(-15)·0
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-41}{2*-15}=\frac{-82}{-30}
=2+11/15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+41}{2*-15}=\frac{0}{-30}
=0
$