32=6u+2(u-2)

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Solution for 32=6u+2(u-2) equation: 



32=6u+2(u-2)

We move all terms to the left:

32-(6u+2(u-2))=0



We calculate terms in parentheses: -(6u+2(u-2)), so:

6u+2(u-2)

We multiply parentheses

6u+2u-4

We add all the numbers together, and all the variables

8u-4

Back to the equation:

-(8u-4)



We get rid of parentheses

-8u+4+32=0

We add all the numbers together, and all the variables

-8u+36=0

We move all terms containing u to the left, all other terms to the right

-8u=-36

u=-36/-8

u=4+1/2

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