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3(x-5)+2=4(2x+10)+2
We move all terms to the left:
3(x-5)+2-(4(2x+10)+2)=0
We multiply parentheses
3x-(4(2x+10)+2)-15+2=0
We calculate terms in parentheses: -(4(2x+10)+2), so:We add all the numbers together, and all the variables
4(2x+10)+2
We multiply parentheses
8x+40+2
We add all the numbers together, and all the variables
8x+42
Back to the equation:
-(8x+42)
3x-(8x+42)-13=0
We get rid of parentheses
3x-8x-42-13=0
We add all the numbers together, and all the variables
-5x-55=0
We move all terms containing x to the left, all other terms to the right
-5x=55
x=55/-5
x=-11
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