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8w^2+2w+2=3
We move all terms to the left:
8w^2+2w+2-(3)=0
We add all the numbers together, and all the variables
8w^2+2w-1=0
a = 8; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·8·(-1)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-6}{2*8}=\frac{-8}{16} =-1/2 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+6}{2*8}=\frac{4}{16} =1/4 $
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