2(n+5)=4-2(n-7)

Solution for 2(n+5)=4-2(n-7) equation:

2(n+5)=4-2(n-7)

We move all terms to the left:

2(n+5)-(4-2(n-7))=0

We multiply parentheses

2n-(4-2(n-7))+10=0


We calculate terms in parentheses: -(4-2(n-7)), so:

4-2(n-7)

determiningTheFunctionDomain
-2(n-7)+4

We multiply parentheses

-2n+14+4

We add all the numbers together, and all the variables

-2n+18

Back to the equation:

-(-2n+18)


We get rid of parentheses

2n+2n-18+10=0

We add all the numbers together, and all the variables

4n-8=0

We move all terms containing n to the left, all other terms to the right

4n=8

n=8/4

n=2