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3(x-5)+1+x=2
We move all terms to the left:
3(x-5)+1+x-(2)=0
We add all the numbers together, and all the variables
x+3(x-5)-1=0
We multiply parentheses
x+3x-15-1=0
We add all the numbers together, and all the variables
4x-16=0
We move all terms containing x to the left, all other terms to the right
4x=16
x=16/4
x=4
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