(2y+41)=(5y+48)

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Solution for (2y+41)=(5y+48) equation: 



(2y+41)=(5y+48)

We move all terms to the left:

(2y+41)-((5y+48))=0

We get rid of parentheses

2y-((5y+48))+41=0



We calculate terms in parentheses: -((5y+48)), so:

(5y+48)

We get rid of parentheses

5y+48

Back to the equation:

-(5y+48)



We get rid of parentheses

2y-5y-48+41=0

We add all the numbers together, and all the variables

-3y-7=0

We move all terms containing y to the left, all other terms to the right

-3y=7

y=7/-3

y=-2+1/3

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