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3(x-4)=3(2x-3)
We move all terms to the left:
3(x-4)-(3(2x-3))=0
We multiply parentheses
3x-(3(2x-3))-12=0
We calculate terms in parentheses: -(3(2x-3)), so:We get rid of parentheses
3(2x-3)
We multiply parentheses
6x-9
Back to the equation:
-(6x-9)
3x-6x+9-12=0
We add all the numbers together, and all the variables
-3x-3=0
We move all terms containing x to the left, all other terms to the right
-3x=3
x=3/-3
x=-1
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