3(r+7)-5(4-r)=5(r-5)

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Solution for 3(r+7)-5(4-r)=5(r-5) equation: 



3(r+7)-5(4-r)=5(r-5)

We move all terms to the left:

3(r+7)-5(4-r)-(5(r-5))=0

We add all the numbers together, and all the variables

3(r+7)-5(-1r+4)-(5(r-5))=0

We multiply parentheses

3r+5r-(5(r-5))+21-20=0



We calculate terms in parentheses: -(5(r-5)), so:

5(r-5)

We multiply parentheses

5r-25

Back to the equation:

-(5r-25)



We add all the numbers together, and all the variables

8r-(5r-25)+1=0

We get rid of parentheses

8r-5r+25+1=0

We add all the numbers together, and all the variables

3r+26=0

We move all terms containing r to the left, all other terms to the right

3r=-26

r=-26/3

r=-8+2/3

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