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(2x-7)(9x+1)=0
We multiply parentheses ..
(+18x^2+2x-63x-7)=0
We get rid of parentheses
18x^2+2x-63x-7=0
We add all the numbers together, and all the variables
18x^2-61x-7=0
a = 18; b = -61; c = -7;
Δ = b2-4ac
Δ = -612-4·18·(-7)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-65}{2*18}=\frac{-4}{36} =-1/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+65}{2*18}=\frac{126}{36} =3+1/2 $
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