3(x-4)+2x=4(x-3)+x

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Solution for 3(x-4)+2x=4(x-3)+x equation: 



3(x-4)+2x=4(x-3)+x

We move all terms to the left:

3(x-4)+2x-(4(x-3)+x)=0

We add all the numbers together, and all the variables

2x+3(x-4)-(4(x-3)+x)=0

We multiply parentheses

2x+3x-(4(x-3)+x)-12=0



We calculate terms in parentheses: -(4(x-3)+x), so:

4(x-3)+x

We add all the numbers together, and all the variables

x+4(x-3)

We multiply parentheses

x+4x-12

We add all the numbers together, and all the variables

5x-12

Back to the equation:

-(5x-12)



We add all the numbers together, and all the variables

5x-(5x-12)-12=0

We get rid of parentheses

5x-5x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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