21=(5/3i)

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Solution for 21=(5/3i) equation: 



21=(5/3i)

We move all terms to the left:

21-((5/3i))=0



Domain of the equation: 3i))!=0

i!=0/1

i!=0

i∈R



We add all the numbers together, and all the variables

-((+5/3i))+21=0

We multiply all the terms by the denominator


-((+5+21*3i))=0



We calculate terms in parentheses: -((+5+21*3i)), so:

(+5+21*3i)

We add all the numbers together, and all the variables

(21*3i+5)

We get rid of parentheses

21*3i+5

Wy multiply elements

63i+5

Back to the equation:

-(63i+5)



We get rid of parentheses

-63i-5=0

We move all terms containing i to the left, all other terms to the right

-63i=5

i=5/-63

i=-5/63

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