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10k^2+200k+937.5=0
a = 10; b = 200; c = +937.5;
Δ = b2-4ac
Δ = 2002-4·10·937.5
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-50}{2*10}=\frac{-250}{20} =-12+1/2 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+50}{2*10}=\frac{-150}{20} =-7+1/2 $
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