3(x-3)-8=7(x-5)

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Solution for 3(x-3)-8=7(x-5) equation:



3(x-3)-8=7(x-5)
We move all terms to the left:
3(x-3)-8-(7(x-5))=0
We multiply parentheses
3x-(7(x-5))-9-8=0
We calculate terms in parentheses: -(7(x-5)), so:
7(x-5)
We multiply parentheses
7x-35
Back to the equation:
-(7x-35)
We add all the numbers together, and all the variables
3x-(7x-35)-17=0
We get rid of parentheses
3x-7x+35-17=0
We add all the numbers together, and all the variables
-4x+18=0
We move all terms containing x to the left, all other terms to the right
-4x=-18
x=-18/-4
x=4+1/2

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