80=4(8)(2)+2(2)h

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Solution for 80=4(8)(2)+2(2)h equation: 



80=4(8)(2)+2(2)h

We move all terms to the left:

80-(4(8)(2)+2(2)h)=0

We add all the numbers together, and all the variables

-(22h+482)+80=0

We get rid of parentheses

-22h-482+80=0

We add all the numbers together, and all the variables

-22h-402=0

We move all terms containing h to the left, all other terms to the right

-22h=402

h=402/-22

h=-18+3/11

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