4y-2=19y+133

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Solution for 4y-2=19y+133 equation: 



4y-2=19y+133

We move all terms to the left:

4y-2-(19y+133)=0

We get rid of parentheses

4y-19y-133-2=0

We add all the numbers together, and all the variables

-15y-135=0

We move all terms containing y to the left, all other terms to the right

-15y=135

y=135/-15

y=-9

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