21(x/3+1)=21(x/7+3)

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Solution for 21(x/3+1)=21(x/7+3) equation: 



21(x/3+1)=21(x/7+3)

We move all terms to the left:

21(x/3+1)-(21(x/7+3))=0

We multiply parentheses

21x-(21(x/7+3))+21=0

We multiply all the terms by the denominator


21x*7+3))-(21(x+21*7+3))=0

We add all the numbers together, and all the variables

21x*7+3))-(21(x+150))=0

We add all the numbers together, and all the variables

21x*7+3))-(21(x=0

Wy multiply elements

147x+3))-(21(x=0

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