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3(x+5)=2+2(x-1)
We move all terms to the left:
3(x+5)-(2+2(x-1))=0
We multiply parentheses
3x-(2+2(x-1))+15=0
We calculate terms in parentheses: -(2+2(x-1)), so:We add all the numbers together, and all the variables
2+2(x-1)
determiningTheFunctionDomain 2(x-1)+2
We multiply parentheses
2x-2+2
We add all the numbers together, and all the variables
2x
Back to the equation:
-(2x)
x+15=0
We move all terms containing x to the left, all other terms to the right
x=-15
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