2y=3(y+1)-20

Solution for 2y=3(y+1)-20 equation:

2y=3(y+1)-20

We move all terms to the left:

2y-(3(y+1)-20)=0


We calculate terms in parentheses: -(3(y+1)-20), so:

3(y+1)-20

We multiply parentheses

3y+3-20

We add all the numbers together, and all the variables

3y-17

Back to the equation:

-(3y-17)


We get rid of parentheses

2y-3y+17=0

We add all the numbers together, and all the variables

-1y+17=0

We move all terms containing y to the left, all other terms to the right

-y=-17

y=-17/-1

y=+17