45=x2+9x-5

Solution for 45=x2+9x-5 equation:

45=x2+9x-5

We move all terms to the left:

45-(x2+9x-5)=0

We add all the numbers together, and all the variables

-(+x^2+9x-5)+45=0

We get rid of parentheses

-x^2-9x+5+45=0

We add all the numbers together, and all the variables

-1x^2-9x+50=0

a = -1; b = -9; c = +50;
Δ = b2-4ac
Δ = -92-4·(-1)·50
Δ = 281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{281}}{2*-1}=\frac{9-\sqrt{281}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{281}}{2*-1}=\frac{9+\sqrt{281}}{-2}
$