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3(x+4)=4(-2x+3)
We move all terms to the left:
3(x+4)-(4(-2x+3))=0
We multiply parentheses
3x-(4(-2x+3))+12=0
We calculate terms in parentheses: -(4(-2x+3)), so:We get rid of parentheses
4(-2x+3)
We multiply parentheses
-8x+12
Back to the equation:
-(-8x+12)
3x+8x-12+12=0
We add all the numbers together, and all the variables
11x=0
x=0/11
x=0
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