Q=400-(2x+15)

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Solution for Q=400-(2x+15) equation: 



=400-(2Q+15)

We move all terms to the left:

-(400-(2Q+15))=0



We calculate terms in parentheses: -(400-(2Q+15)), so:

400-(2Q+15)

determiningTheFunctionDomain
-(2Q+15)+400

We get rid of parentheses

-2Q-15+400

We add all the numbers together, and all the variables

-2Q+385

Back to the equation:

-(-2Q+385)



We get rid of parentheses

2Q-385=0

We move all terms containing Q to the left, all other terms to the right

2Q=385

Q=385/2

Q=192+1/2

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