(x+1)+(3x-2)+(2x-5)=0

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Solution for (x+1)+(3x-2)+(2x-5)=0 equation: 



(x+1)+(3x-2)+(2x-5)=0

We get rid of parentheses

x+3x+2x+1-2-5=0

We add all the numbers together, and all the variables

6x-6=0

We move all terms containing x to the left, all other terms to the right

6x=6

x=6/6

x=1

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