3(x+2)-7x=6(x+2)-x

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Solution for 3(x+2)-7x=6(x+2)-x equation: 



3(x+2)-7x=6(x+2)-x

We move all terms to the left:

3(x+2)-7x-(6(x+2)-x)=0

We add all the numbers together, and all the variables

-7x+3(x+2)-(6(x+2)-x)=0

We multiply parentheses

-7x+3x-(6(x+2)-x)+6=0



We calculate terms in parentheses: -(6(x+2)-x), so:

6(x+2)-x

We add all the numbers together, and all the variables

-1x+6(x+2)

We multiply parentheses

-1x+6x+12

We add all the numbers together, and all the variables

5x+12

Back to the equation:

-(5x+12)



We add all the numbers together, and all the variables

-4x-(5x+12)+6=0

We get rid of parentheses

-4x-5x-12+6=0

We add all the numbers together, and all the variables

-9x-6=0

We move all terms containing x to the left, all other terms to the right

-9x=6

x=6/-9

x=-2/3

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