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-6-(3x-2)=5x-4(2x+1)
We move all terms to the left:
-6-(3x-2)-(5x-4(2x+1))=0
We get rid of parentheses
-3x-(5x-4(2x+1))+2-6=0
We calculate terms in parentheses: -(5x-4(2x+1)), so:We add all the numbers together, and all the variables
5x-4(2x+1)
We multiply parentheses
5x-8x-4
We add all the numbers together, and all the variables
-3x-4
Back to the equation:
-(-3x-4)
-3x-(-3x-4)-4=0
We get rid of parentheses
-3x+3x+4-4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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