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1/5x=5-x
We move all terms to the left:
1/5x-(5-x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x-(-1x+5)=0
We get rid of parentheses
1/5x+1x-5=0
We multiply all the terms by the denominator
1x*5x-5*5x+1=0
Wy multiply elements
5x^2-25x+1=0
a = 5; b = -25; c = +1;
Δ = b2-4ac
Δ = -252-4·5·1
Δ = 605
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{605}=\sqrt{121*5}=\sqrt{121}*\sqrt{5}=11\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-11\sqrt{5}}{2*5}=\frac{25-11\sqrt{5}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+11\sqrt{5}}{2*5}=\frac{25+11\sqrt{5}}{10} $
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