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3(x+2)-2x=4(x-3)+6
We move all terms to the left:
3(x+2)-2x-(4(x-3)+6)=0
We add all the numbers together, and all the variables
-2x+3(x+2)-(4(x-3)+6)=0
We multiply parentheses
-2x+3x-(4(x-3)+6)+6=0
We calculate terms in parentheses: -(4(x-3)+6), so:We add all the numbers together, and all the variables
4(x-3)+6
We multiply parentheses
4x-12+6
We add all the numbers together, and all the variables
4x-6
Back to the equation:
-(4x-6)
x-(4x-6)+6=0
We get rid of parentheses
x-4x+6+6=0
We add all the numbers together, and all the variables
-3x+12=0
We move all terms containing x to the left, all other terms to the right
-3x=-12
x=-12/-3
x=+4
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