4(-3-3y)=-5(y+8)

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Solution for 4(-3-3y)=-5(y+8) equation: 



4(-3-3y)=-5(y+8)

We move all terms to the left:

4(-3-3y)-(-5(y+8))=0

We add all the numbers together, and all the variables

4(-3y-3)-(-5(y+8))=0

We multiply parentheses

-12y-(-5(y+8))-12=0



We calculate terms in parentheses: -(-5(y+8)), so:

-5(y+8)

We multiply parentheses

-5y-40

Back to the equation:

-(-5y-40)



We get rid of parentheses

-12y+5y+40-12=0

We add all the numbers together, and all the variables

-7y+28=0

We move all terms containing y to the left, all other terms to the right

-7y=-28

y=-28/-7

y=+4

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